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o-na [289]
3 years ago
13

As of a certain date, there had been a total of 14,649 performances of two shows on Broadway, with 2389 more performances of Sho

w A than Show B. How many performances were there of each show? There were performances for Show A.​
Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Subtract the difference:

14,649 - 2389 = 12,260

Divide that by 2

12,260 / 2 = 6,130

That is the number of shows for B.

For A add the 2,389 to the number of shows for B

2389 + 6130 = 8,519

Show A = 8,519

Show B = 6,130

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no solutions

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