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3 years ago

E=mc^2 solve for c please help will mark brainliest

Mathematics

2 answers:

dimaraw [331]3 years ago

8 0

Answer:

c = ± $\sqrt{\frac{e}{m} }$

Step-by-step explanation:

Given

e = mc² ( divide both sides by m to isolate c² )

$\frac{e}{m}$ = c² ( take the square root of both sides )

c = ± $\sqrt{\frac{e}{m} }$

Tanzania [10]3 years ago

7 0

Answer:

c= - (sqr em)/m

Step-by-step explanation:

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X varies directly with y. If x is 16 when y is 20, find x when y is 80.

Taya2010 [7]

Answer:

Step-by-step explanation:

16/20 reduces down to 2/5

set 2/5=x/80

cross multiply 160=5x

divide 32=x

check 2/5=32/80

32/80; 16/40; 8/20; 4/10; 2/5

yay 32 is the answer good luck :)

5 0

3 years ago

This is to confusing

erastova [34]

Answer:

Step-by-step explanation:

because there is 10 parts and if the 10 multipied by 10 (to find the percent) is 100 then the 4 is 40 (the unshaded part would be 60%)

Have a fantastic day!

7 0

3 years ago

Help me plzz please

professor190 [17]

Answer:

0.05m=5cm

8x5/2=20cm²

hope it'll help you

3 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

son4ous [18]

Answer:

<YXZ and <TUS

Step-by-step explanation:

An exterior angle is found outside the parallel line. When you have two exterior angles that are opposite each other along the transversal, they are referred to as alternate exterior angles.

Therefore, the only pair of angles from the given options that flare alternate exterior angles are:

<YXZ and <TUS

4 0

3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

6 0

3 years ago

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