Answer:
28 inch
Step-by-step explanation:
The length of all four sides of square is equal.
The formula used for finding the area of square is:
Area = (Length) × (Length)
Thus, the Area of square whose length is 2√7 is:
Area = 2√7 × 2√7
⇒ Area = 4 × 7 = 28 inch.
Answer:

Step-by-step explanation:
Let
x ----> the number of t-shirts
y ----> the cost of buying T-shirts from Paula’s Printing in dollars
take two points from the given data
we have
(2,43) and (4,86)
step 1
Find the slope
The formula to calculate the slope between two points is equal to
substitute the values in the formula
step 2
Find the equation of the line in point slope form

we have

substitute

step 3
Convert to slope intercept form

Isolate the variable y



This linear equation represent a proportional relationship (the line passes through the origin)
I think the answer is C) all positive integers. It makes the most sense in the context of the problem.
The true statements are;
1) AB + BC = AC
Length of BC = |6 - 1|
2) ∠JMK = 50°
∠KML = 35°
<h3>How to Interpret Number Line intervals?</h3>
1) From the given number line interval, we can deduce the interpretation as follows;
AB + BC = AC
Length of BC = 5 units or |6 - 1|
Length of B = 3 Units
2) We can see that ∠JML is an angle triangle. Thus, ∠JML = 85°. Thus;
6x + 2 + 4x + 3 = 85
10x + 5 = 85
10x = 85 - 5
10x = 80
x = 80/10
x = 8°
Thus;
∠JMK = 6(8) + 2
∠JMK = 50°
∠KML = 85° - 50°
∠KML = 35°
Read more about Number Line Intervals at; brainly.com/question/27998235
#SPJ1
Answer:
D
Step-by-step explanation:
First, let's find <em>x</em>.
We know that one of the angles is 30. The side opposite to than angle is 11, and <em>x</em> is the adjacent side to it. Therefore, we can use the trig function tangent.
Recall that:

Plug in 30 for the angle, 11 for the opposite, and <em>x</em> for the adjacent. Solve for <em>x</em> by cross-multiplying:

From the unit circle, recall that tan(30) is equal to one over the square root of 3. Thus:

Now, we can use the Pythagorean Theorem to find <em>y</em>. <em>y</em> is the hypotenuse. Thus:
