Solve for 2/3(9 - 6) + 40 and 7/8 - (-1/10) + (-3/5)
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The equations for the horizontal and vertical lines passing through the point (6,9) is y = 9 and x = 6 respectively
<u>Solution:</u>
Given, point is (6, 9)
We have to find the equations for horizontal and vertical lines passing through above given point.
Now, let us find horizontal line,
We know that, horizontal line is parallel to x – axis, so slope of our required line is 0.
The point slope form is given as
Then, line equation in point slope form ⇒ y – 9 = 0(x – 6)
⇒ y – 9 = 0
⇒ y = 9
Now, let us find vertical line,
We know that, vertical line is parallel to y – axis, so slope of our required line is undefined
Then, line equation in point slope form ⇒
⇒ x – 6 = 0(y – 9)
⇒ x – 6 = 0
⇒ x = 6
Hence, the horizontal line equation is y = 9 and vertical line equation is x = 6.
The two z-scores are -1.53 and 1.53
Step-by-step explanation:
To find the two z-scores that separate the middle 87.4% of the distribution from the area in the tails of the standard normal distribution
- Assume that z-score is between -c and c ⇒ P(-c < z < c) = the given value
- Find the value of P(z < -c or z > c) = 1 - the given value
- P(z < -c) + P(z > c) = the answer of the previous step
- 2*P(z < -c) = the answer of the previous step
- Find the value of P(z < -c)
- In the z-table having area to the left of z, look for the value closest to the value of P(z < -c) inside the table to find the closest value of z
∵ P(-c < z < c) = 87.4%
∵ 87.4% = 87.4 ÷ 100 = 0.874
∴ P(-c < z < c) = 0.874
∵ P(z > c) = 1 - 0.874 = 0.126
∴ P(z < -c) + P(z > c) = 0.126
∵ P(z > c) = P(z < -c)
∴ P(z < -c) + P(z < -c) = 0.126
∴ 2*P(z < -c) = 0.126
- Divide both sides by 2
∴ P(z < -c) = 0.063
Let us use the z-table to find the corresponding values of
z to 0.063
∵ The corresponding value of z to 0.063 = -1.53
∴ The two z-scores = -1.53 and 1.53
The attached figure for more understand
The two z-scores are -1.53 and 1.53
Learn more:
You can learn more about z-score in brainly.com/question/6270221
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