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3 years ago

How do i prove this?

Mathematics

1 answer:

Radda [10]3 years ago

4 0

you first have to simfly in the partithies always then solve and prove done!

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In the diagram, BC¯¯¯¯¯∥DE¯¯¯¯¯ .<br><br> What is AE ?

emmainna [20.7K]

So there are two triangles here: Smaller one (ADE) and bigger one (ABC) and they both are similar.

So you can use proportions here.

AB / AC = AD / AE

AB = AD + DB = 6 + 1 = 7
AC = AE + 3

AD = 6

So plug in these values:

AB / AC = AD / AE becomes
7 / (AE + 3) = 6 / AE

Now do the cross multiply:

7 AE = 6 (AE + 3)

Now solve for AE:

7AE = 6AE + 18

AE = 18

6 0

3 years ago

I need help with this question... the topic is solving linear systems of equations using elimination (addition). Please give exp

gregori [183]

Answer:

x= -1

y=2

Step-by-step explanation:

6x+5y=4

6x-7y=-20

Subtract

7 0

3 years ago

the area of a rectangle is x²-3x-10. what is the length of the rectangle if the with is x +2.?plsss asap

Inga [223]

Answer:

x - 5

Step-by-step explanation:

x^2 - 3x - 10

= (x + 2)(x - 5)

Sine the width is (x + 2), the length is (x - 5).

Hope this helped!

7 0

3 years ago

Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo

elena55 [62]

Answer:

$\displaystyle y-5=-\frac{10}{9}(x+6)$

Or:

$\displaystyle y+5=-\frac{10}{9}(x-3)$

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

$y-y_1=m(x-x_1)$

Thus, first, we need to find the slope. We can use the slope formula:

$\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}$

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

$\displaystyle y-(5)=-\frac{10}{9}(x-(-6))$

Or, fully simplified:

$\displaystyle y-5=\frac{-10}{9}(x+6)$

Using the other point, we will acquire:

$\displaystyle y-(-5)=-\frac{10}{9}(x-(3))$

Or, simplified:

$\displaystyle y+5=-\frac{10}{9}(x-3)$

8 0

3 years ago

Factor the polynomial 16b^4+30b^3-12b^2

Lelu [443]

Answer:

2b²(8b²+15b-6)

Step-by-step explanation:

16 $b^{4}$ +30b³-12b²

2b²(8b²+15b-6)

This is not further factorable. If you want to find the roots, you'd have to use the quadratic formula for the polynomial in the parentheses. Therefore that is our final answer.

4 0

3 years ago