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stepladder [879]
3 years ago
5

I need help......................

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

a) false

b) true

c) true

d) false

hope dis helps ^-^

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Answer these Questions for me pleaseeeee....
Thepotemich [5.8K]

Answer:

A. 31

B. 5

C. 9/31 or 0.29%

D. 2/31 or 0.06%

E. 0 or unknown

Step-by-step explanation:

A is the addition of all the entries, B is the number of entries that said snakes, C and D are about how many out of the total can give you the corresponding animal, chances are always part/total so for C it's 9/31 and D is 2/31. E is 0 or unknown because there is no "Frog" entries as favorite pet so it must be either 0 or unknown because you don't get the information

<em>pls brainliest if you found useful</em>

3 0
3 years ago
You pay .50 cent to draw a card from a deck. if you draw an ace you win ten dollars if you draw a face card(12 in a deck) you wi
sveticcg [70]
The probability that a face card can be drawn from a standard deck of cards is 12/52 which can be simplified into 3/13.

The expected value is the product of the probability and the value.
                       Expected value = (3/13)($1) = $0.23
The difference between the amount spent and the expected value is equal to $0.27.
5 0
3 years ago
How many women must be randomly selected to estimate the mean weight of women in one age group? We want 90% confidence that the
ki77a [65]

Answer:

155 women must be randomly selected.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The population standard deviation is known to be 28 lbs.

This means that \sigma = 28

We want 90% confidence that the sample mean is within 3.7 lbs of the populations mean. How many women must be sampled?

This is n for which M = 3.7. So

M = z\frac{\sigma}{\sqrt{n}}

3.7 = 1.645\frac{28}{\sqrt{n}}

3.7\sqrt{n} = 1.645*28

\sqrt{n} = \frac{1.645*28}{3.7}

(\sqrt{n})^2 = (\frac{1.645*28}{3.7})^2

n = 154.97

Rounding up:

155 women must be randomly selected.

4 0
3 years ago
Which of the following is most likely the value of the seventh term of the sequence graphed below?
IRISSAK [1]
I think the answer is A. Hope it help!
4 0
3 years ago
Read 2 more answers
100PNTS! I desperately need help/answers to these please :(
kotykmax [81]

Answer:

1a- Alternate Exterior Angles

1b- Alternate Interior Angles

1c-Alternate Exterior Angles

1d-Alternate Interior Angles

1e-Alternate Exterior Angles

1f-Alternate Interior Angles

2a-None

2b-None

2c-Alternate Exterior Angles

2d-None

2e-Alternate Interior Angles

2f-None

2g-None

2h-None

2i-None

2j-None

6 0
3 years ago
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