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2 years ago

Given f(x)=2x+4 and g(x)=x2−4, determine the value of (5) + (−3).

Mathematics

2 answers:

babunello [35]2 years ago

6 0

Answer:

c 41

Step-by-step explanation:

Substitute 5 in and it is 2^5 not 2*5 so that would be 32 not 10 and then just

add and subtract and multiply the rest and it's 41

Irina18 [472]2 years ago

5 0

Answer:

None of the above, f(5) + g(-3) = 19.

Step-by-step explanation:

Given f(x)=2x+4 and g(x)=x2−4, determine the value of (5) + (−3). Assume that is supposed to be f(5) + g(-3).

f(5) + g(-3) = 2×5 + 4 + (-3)^2 - 4

= 10 + 4 - 4 + (-1)^2(3)^2

= 19

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Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x

Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

$f(x) = (x - (7 + i)) (x - (5 - i))$

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

$f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))$

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

$f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48$

5 0

1 year ago

Please help will mark brainliest

beks73 [17]

Answer:

$m\angle N=57^{\circ}$

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares $LM\cong LN$ , the remaining unknown angles are equal ( $m\angle N=m\angle M$ ). The sum of the interior angles of a triangle always add up to $180^{\circ}$$ .

Therefore:

$m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$}$ .

7 0

2 years ago

Read 2 more answers

Consider all angles whose reference angle is 45° with terminal sides not in Quadrant I.The angles that share the same cosine val

Oksana_A [137]

Solution:

As we know reference angle is smallest angle between terminal side and X axis.

As cosine 45 ° is always positive in first and fourth quadrant.

i.e CosФ, Cos (-Ф) or Cos(2π - Ф) have same value.

As, Cos 45°, Cos (-45°) or Cos ( 360° - 45°)= Cos 315°are same.

So, Angles that share the same Cosine value as Cos 45° have same terminal sides will be in Quadrant IV having value Either Cos (-45°) or Cos (315°).

Also, Cos 45° = Sin 45° or Sin 135° i.e terminal side in first Quadrant or second Quadrant.