I’m not really sure but I would have to guess 4.5 because all of the other numbers don’t have decimals
Judging by the question at hand I generated this equation.
x+y=12
x=2y
I begin this question by plugging in the x=2y into the equation for x.
So the new equation should be 3y=12. I then divide the entire equation by 3 to get y=4.
Next I plug y=4 into the equation, the new equation should be x+4=12. I then subtract 4 from both sides to get x=8.
The two numbers are :
x=8 y=4
Answer:
<em>The equation of the straight line in point - slope form</em>
<em>y +1 = -2 ( x-2)</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are C( 2,-1) and D(1,1)
Slope of the line
m = -2
<u>Step(ii):-</u>
Equation of the straight line passing through the point ( 2,-1) and having slope
m =-2
y - y₁ = m ( x- x₁)
y - (-1) = -2 ( x-2)
y +1 = -2 ( x-2)
<u><em>Final answer:-</em></u>
<em>The equation of the straight line</em>
<em>y +1 = -2 ( x-2)</em>
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
