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Scilla [17]
3 years ago
9

About 0.5 of all the students in the fifth grade are girls. If the fifth grade has 80 ​students, how many of the students are gi

rls​?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

40 Girls.

Step-by-step explanation:

80 multipled by 0.5 = 40

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What is 20% of 500ml
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100ml u see 20% of 100 is 20 20% of 1000 is 200 so divide 200/2 =100
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Write an exponential function in the form y = ab that goes through points (0,19)<br>and (5,4617).​
gtnhenbr [62]

Answer:

y = 1/2 (2)x

     Step-by-step explanation:

Using the equation y = abx , substitute both of your given points into that equation.

2 = ab2 and 4 = ab3   Solve each equation for a.

2⁄b2    and 4⁄b3 = a     Therefore, 2⁄b2 = 4⁄b3

                             

Cross multiply: 2b3 = 4b2     Divide both sides by b2

2b = 4      a = 2/4 = 1/2

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Bethany sells roses and petunias. The expression 3r+2.5p gives the cost (in dollars) of r roses and pp petunias. What is the cos
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(3×7)+(2.5×8)=(21)+(20)=$41
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3 years ago
PLEASE HELP!!! In a set of 1,000 integers from 1 to 1,000, an integer chosen at random on a single trial should be an integer fr
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Answer:

Step-by-step explanation:

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3 0
3 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
4 years ago
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