The cost of each notebook is $ 2.3 and cost of each thumb drive is $ 4.85
<em><u>Solution:</u></em>
Let "a" be the cost of each notebook
Let "b" be the cost of each thumb drive
Given that,
<em><u>6 notebooks and 4 thumb drives costs 33.2</u></em>
Therefore,
6 notebook x cost of each notebook + 4 thumb drive x cost of each thumb drive = 33.2
![6 \times a + 4 \times b = 33.2](https://tex.z-dn.net/?f=6%20%5Ctimes%20a%20%2B%204%20%5Ctimes%20b%20%3D%2033.2)
6a + 4b = 33.2 ----------- eqn 1
<em><u>5 notebooks and 5 thumb drives costs 35.75</u></em>
5 notebook x cost of each notebook + 5 thumbdrive x cost of each thumb drive = 35.75
![5 \times a + 5 \times b = 35.75](https://tex.z-dn.net/?f=5%20%5Ctimes%20a%20%2B%205%20%5Ctimes%20b%20%3D%2035.75)
5a + 5b = 35.75 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 5</u></em>
30a + 20b = 166 ----------- eqn 3
Multiply eqn 2 by 6
30a + 30b = 214.5 ---------- eqn 4
Subtract eqn 3 from eqn 4
30a + 30b = 214.5
30a + 20b = 166
( - ) -----------------
10b = 48.5
Divide both sides by 10
<h3>b = 4.85</h3>
<em><u>Subtsitute b = 4.85 in eqn 1</u></em>
6a + 4(4.85) = 33.2
6a + 19.4 = 33.2
6a = 13.8
Divide both sides by 6
<h3>a = 2.3</h3>
Thus cost of each notebook is $ 2.3 and cost of each thumb drive is $ 4.85