What is the surface area of the rectangular pyramid

Mathematics

1 answer:

posledela3 years ago

3 0

Answer:

Step-by-step explanation:

We have:

rectangle 4.8 m × 3.8 m

two triangles with base b = 4.8 m and height h = 2.6 m

two triangle with base b = 3.8 m and height h = 2.9 m.

The formula of an area of a rectangle l × w:

$A = lw$

Substitute:

$A_1 = (4.8)(3.8) = 18.24\ m^2$

The formula of an area of a triangle:

$A=\dfrac{bh}{2}$

Substitute:

$A_2=\dfrac{(4.8)(2.6)}{2}=6.24\ m^2\\\\A_3=\dfrac{(3.8)(2.9)}{2}=5.51\ m^2$

The Surface Area:

$S.A.=A_1+2A_2+2A_3\\\\S.A.=18.24+2(6.24)+2(5.51)=41.74\ m^2$

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$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

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