Answer:
73 nickels, 27 dimes
Step-by-step explanation:
x+y=100
5x+10y=635
x=100-y
5(100-y)+10y=635
500-5y+10y=635
500+5y=635
5y=135
y=27
5x+10(27)=635
5x+270=635
5x=365
73
73+27=100
Answer:
The values of x and y in the diagonals of the parallelogram are x=0 and y=5
Step-by-step explanation:
Given that ABCD is a parallelogram
And segment AC=4x+10
From the figure we have the diagonals AC=3x+y and BD=2x+y
By the property of parallelogram the diagonals are congruent
∴ we can equate the diagonals AC=BD
That is 3x+y=2x+y
3x+y-(2x+y)=2x+y-(2x+y)
3x+y-2x-y=2x+y-2x-y
x+0=0 ( by adding the like terms )
∴ x=0
Given that segment AC=4x+10
Substitute x=0 we have AC=4(0)+10
=0+10
=10
∴ AC=10
Now (3x+y)+(2x+y)=10
5x+2y=10
Substitute x=0, 5(0)+2y=10
2y=10
∴ y=5
∴ the values of x and y are x=0 and y=5
Answer:
Ratio 4 is for Caroline, ratio 5 is for krutika, ratio 1 is for Natasha
Answer:
Number of each ticket is;
$10 tickets = 1115
$20 tickets = 1251
$30 tickets = 934
Step-by-step explanation:
Let x,y and z represent the number of $10,$20 and $30 tickets sold.
Given;
Total number of tickets n = 3300
x+y+z = 3300 .....1
Total sales = $64,190
10x + 20y + 30z = 64,190 .....2
It has sold 136 more $20 tickets than $10 tickets
y = x +136 ........3
Substituting equation 3 into equation 1 and 2;
For 1;
x+y+z = 3300
x+(x+136)+z = 3300
2x + z = 330-136
2x + z = 3164 ........4
For 2;
10x + 20y + 30z = 64,190
10x + 20(x+136) + 30z = 64,190
10x + 20x + 2720 + 30z = 64190
30x + 30z = 64190-2720
30x+30z = 61470
divide through by 30
x+z = 2049 ......5
Subtract equation 5 from 4
2x-x +z-z = 3164-2049
x = 1115
From equation 3
y = x + 136 = 1115+136
y = 1251
From equation 1;
z = 3300 - (x+y)
z = 3300- (1115 + 1251)
z = 934
Number of each ticket is;
$10 tickets = 1115
$20 tickets = 1251
$30 tickets = 934
We see that is a rectangle+1/2 circle
area of circle=pir^2
area of rectangle=LW or LH or something
aera of recctangle=2 times 1.5=3
area of half cirlce=1/2 times 3.14 times 1.5^2=1.57 times 2.25=3.5325
add
3+3.5325=6.5325 ft^2
area=6.5325 ft^2
round if nececary
