Answer:
h = 1,268 cm
Step-by-step explanation:
V = (π·r²·h)/3, general formula
83 = (π·4²·h)/3, substitute what is given V= 83 cm³ and r = 4 cm
83 ·3 = (π· 16·h)·3/3, multiply both sides by 3 and solve 4² = 16
249 = π·16·h, multiply 83·3 = 249 and 3/3 = 1
249/ π·16 = h , divide both sides by π·16
1,268.146587 = h, solve
1,268 ≈ h , is rounded to the nearest cm
Answer:
y - 1 = (1/3)(x + 2)
Step-by-step explanation:
Here m = 1/3 and (-2, 1) is a point on the line. The appropriate equation is
y - k = m(x - h), where (h, k) is the pt on the line.
Subbing the known values, we get:
y - 1 = (1/3)(x + 2)
Your answer would be -1.3
You need to make a draw of the problem to understand what to do.
The height of the pyramid, and half the original base side length make a rectangle triangle, whose hypothenuse is the height of the lateral area of one of the pyramids faces, so we have. So we use Pythagoras:
hyp^2 = 11^2 + 14^2 = 317
hyp = 17.8 m
that is the height of the lateral area triangle
Now to find the area of the lateral area triangle, we have:
a = base*height/2 = 22*17.8/2
a = 195.8 m^2
that is the lateral area of the pyramid, 196 m^2
Answer:
66.7%
Step-by-step explanation:
The numbers less than 7 on the list are 3, 4, 5, and 6.
4 numbers are less than 7 out of total 6 numbers.
4/6 = 2/3 = 0.667 = 66.7%
