First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
5 candies
Step-by-step explanation:
Total of candy Sarah has = 25candies
If Sarah gave 2/5 of the candies to her sister, the total amount she gave her sister will be 2/5 of 25
2/5 of 25 = 10
The remaining candy left will be 25-10 which is 15.
If she gave 2/3 of amount left to her friend, the amount she gave her friend will be 2/3×15 = 10candies.
The amount of candy Sarah have left will be 15- 10 which is 5candies.
A rhombus is quadrilateral where all 4 sides are of equal length. Thus
5x + 2 = 2x + 12
3x = 10
x = 10/3
substituting x into either expression, yields
56/3
therefore side AB = 56/3
Answer:
D. –5.2 + (–6.4) = –11.6
Step-by-step explanation:
First, you can eliminate A and C because 5.2 is positive. Since the red arrow is pointing left, it indicates that the number (-5.2) is negative.
Then, you look at the second arrow, the green one. It is pointing left, so it would be -6.4.
I hope this helps :)
