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Ann [662]
2 years ago
9

The expression 9x ^(2)-5x -7 has___ terms and a constant of ____ .

Mathematics
1 answer:
Elenna [48]2 years ago
8 0

The expression 9x ^2-5x -7 has_3__ terms and a constant of __-7__ .

Step-by-step explanation:

The expression 9x ^2-5x -7 has___ terms and a constant of ____ .

Each term in an expression is separated by + or -

A constant is a term in an expression that contains only numbers. It doesn't have variables in it.

So, in the given expression  9x ^2-5x -7

Terms : 3 i.e, 9x^2, 5x, 7

and constant = -7

The expression 9x ^2-5x -7 has_3__ terms and a constant of __-7__ .

Keywords: Terms and Constants

Learn more about Terms and Constants at:

  • brainly.com/question/4934417
  • brainly.com/question/12363217
  • brainly.com/question/12700460

#learnwithBrainly

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What two cars, I don’t see anything
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Convert the following fraction to a decimal.
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I think it’s C but I could be wrong but I don’t think I am
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What are the y-intercept of the function f(x)=-2x^2-3x+20?
Serhud [2]

Answer:

\sf A) \ (-4, \ 0) \ and \ \  [\dfrac{5}{2} , \ 0]

Explanation:

Given function: f(x) = -2x² - 3x + 20

To find the x-intercepts of a function, f(x) = 0

=================

-2x² - 3x + 20 = f(x)

-2x² - 3x + 20 = 0

-2x² - 8x + 5x + 20 = 0

-2x(x + 4) + 5(x + 4) = 0

(-2x + 5) (x + 4) = 0

-2x + 5 = 0, x + 4 = 0

-2x = -5, x = -4

x = -5/-2,x = -4

x = 5/2, x= -4

Coordinates: (-4, 0), (5/2, 0)

4 0
2 years ago
Mr. Burn's class is taking a field trip to the planetarium. The trip will cost $27 for each
marysya [2.9K]

Answer:

$486

Step-by-step explanation:

all you do is multiply 27 and 18. i feel like using compatible numbers bc the numbers you have will give you your answer.

7 0
2 years ago
Read 2 more answers
If
likoan [24]

It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

Then the integral is bounded by

\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)

\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

7 0
2 years ago
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