The area of a triangle can be calculated as half the product of base length and height. We want the area to be no greater than 10 in².
a) (1/2)(4)(2x-3) ≤ 10
b) 4x -6 ≤ 10 . . . . . simplify
... 4x ≤ 16 . . . . . . . .add 6
... x ≤ 4 . . . . . . . . . divide by the coefficient of x
c) The maximum value of (2x -3) in is (2·4 -3) in = 5 in.
The triangle should be no more than 5 in high to have an area less than 10 in².
Answer:
A and D have whole grid squares that are the same size and aren't over lapping
C has overlapping grid squares making it hard to count
B can't be used to find area because some of the grid squares are different sizes
You still could use B because four of the smaller squares seems to be equivalent to one of the larger squares
Step-by-step explanation:
Answer:
= -3i + (3/4+2i) - (9/3+3i)
= (3/4 - 9/3) + (-3 + 2 -3)i
= -9/4 -4i
Answer:
48:36 64:48 60:80
Step-by-step explanation:
Answer:
y = 2x - 9
Step-by-step explanation:
y2 - y1 / x2 - x1
9 - (-1) / 9 - 4
10 / 5
= 2
y = 2x + b
-1 = 2(4) + b
-1 = 8 + b
-9 = b
