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ozzi
1 year ago
7

A rectangular field has a perimeter of 300m. What is the area of the field if the length of the field is twice the width of the

field
Mathematics
2 answers:
igomit [66]1 year ago
3 0

Answer: 120

Step-by-step explanation:

If the W = x, then L = 4x

Perimeter = 2(L+W) = P

2(4x+x) = 300

2(5x) = 300

10x = 300

x = 30

W = x = 30

L = 4x = 4(30) = 120

dusya [7]1 year ago
3 0

Answer:

5000 square meters

Step-by-step explanation:

Create a rectangle and use any variable to lable it.

I used c and I know that the length is twice the width, so I added "c" for both widths and "2c" for both lengths.

Count the number of c's up and you will get 6.

Divide 300/6 to get the value for c.

You get 50 for c, so plug it in for the length 2(50) or 100, and plug it in for the width or 1(50).

Now that you have the length and width of the triangle, use length times width to find the area.

100x50=5000

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4 0
2 years ago
AB, CD, and EF intersect at O. If CD is perpendicular to EF and m
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Answer:

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Step-by-step explanation:

From the figure attached,

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3 years ago
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DaniilM [7]

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3 years ago
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Below.

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2 years ago
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