A rectangular field has a perimeter of 300m. What is the area of the field if the length of the field is twice the width of the
field
2 answers:
Answer: 120
Step-by-step explanation:
If the W = x, then L = 4x
Perimeter = 2(L+W) = P
2(4x+x) = 300
2(5x) = 300
10x = 300
x = 30
W = x = 30
L = 4x = 4(30) = 120
Answer:
5000 square meters
Step-by-step explanation:
Create a rectangle and use any variable to lable it.
I used c and I know that the length is twice the width, so I added "c" for both widths and "2c" for both lengths.
Count the number of c's up and you will get 6.
Divide 300/6 to get the value for c.
You get 50 for c, so plug it in for the length 2(50) or 100, and plug it in for the width or 1(50).
Now that you have the length and width of the triangle, use length times width to find the area.
100x50=5000
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Answer:
384
Step-by-step explanation:
I think its 384 I say I think
You do 3 x 8 / 100 to work out 3/8 as a decimal. So its 0.24. 0.38 is bigger
It would be 14 for the perimeter
Make the number 693,000 instead of 69,300. The answer would be 86,625.
Hope this helped, I wasn’t to sure on what you were asking though.