PART A
The equation of the parabola in vertex form is given by the formula,

where

is the vertex of the parabola.
We substitute these values to obtain,

The point, (3,6) lies on the parabola.
It must therefore satisfy its equation.




Hence the equation of the parabola in vertex form is

PART B
To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

This implies that

We expand to obtain,

This will give us,


This equation is now in the form,

where

This is the standard form
Box and it has parallel lines and it has a perpendicular degrees of 90%
Answer:
Is 11
Step-by-step explanation:
x+(-y)+z —> -5 +(+7)+9 = -5+7+9 = 11
Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.
Combined Area = (2x + 26)*(2x + 8) = 1008
2x*(2x + 8) + 26*(2x + 8 ) = 1008
4x² + 16x + 52x + 208 = 1008
4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0. Divide through by 4.
x² + 17x - 200 = 0 . This is a quadratic equation.
Multiply first and last coefficients: 1*-200 = -200
We look for two numbers that multiply to give -200, and add to give +17
Those two numbers are 25 and -8.
Check: 25*-8 = -200 25 + -8 = 17
We replace the middle term of +17x in the quadratic expression with 25x -8x
x² +17x - 200 = 0
x² + 25x - 8x - 200 = 0
x(x + 25) - 8(x + 25) = 0
(x+25)(x -8) = 0
x + 25 = 0 or x - 8 = 0
x = 0 -25 x = 0 + 8
x = -25 x = 8
The width of the path can not be negative.
The only valid solution is x = 8.
The width of the path is 8 meters.