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o-na [289]
3 years ago
12

Using six random samples, the average number of catfish in the samples was 5.7. If the total population of fish in the pond is 2

00, the proportion of catfish in the pond will be 5.7 20 = x 200 . What is the predicted number of catfish in the pond?
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
8 0

Answer:57 = x

Step-by-step explanation:

Using the proportion given, there will be 57 catfish in the pond.

The proportion given to us is

5.7/20 = x/200

Cross multiply:

5.7*200 = 20*x

1140 = 20x

Divide both sides by 20:

1140/20 = 20x/20

57 = x

zheka24 [161]3 years ago
5 0
Using the proportion given, there will be 57 catfish in the pond.

The proportion given to us is
5.7/20 = x/200

Cross multiply:
5.7*200 = 20*x
1140 = 20x

Divide both sides by 20:
1140/20 = 20x/20
57 = x
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The height of a soccer ball that is kicked from the ground can be approximated by the function:
AfilCa [17]

Answer:

\displaystyle \sqrt{3}\:sec.

Step-by-step explanation:

\displaystyle -54 = -18x^2 → \frac{-54}{-18} = \frac{-18x^2}{-18} \\ \\ 3 = x^2 → \sqrt{3} = x

I am joyous to assist you anytime.

6 0
3 years ago
Which graph represents this exponential function? f(x)=3(2)^x-4
Rasek [7]

Answer:

A

Step-by-step explanation:

look up desmos graphing calculator and it graphs all of your equations for you. I used it all through high school.

4 0
3 years ago
A group of campers is going to occupy 6 campsites at a campground. There are 16 campsites from which to choose. In how many ways
Pachacha [2.7K]

Answer:

The campsites can be chosen in 5,765,760 different ways.

Step-by-step explanation:

Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:

16 x 15 x 14 x 13 x 12 x 11 = X

240 x 182 x 132 = X

240 x 24,024 = X

5,765,760 = X

Therefore, the campsites can be chosen in 5,765,760 different ways.

8 0
3 years ago
The formula for the size of a file that was downloaded over time t and at an average rate r is r.t.
lakkis [162]

Answer:

The size of file downloaded is  <em>88 megabytes.</em>

Step-by-step explanation:

Given that:

Average rate of downloading the file = r

Time taken to download = t

Formula for the size of file downloaded = r.t

Rate of downloading, r = 800\ kilobytes/sec

Time taken, t = 110 seconds

To find:

Size of file downloaded in megabytes = ?

Solution:

First of all, let us apply the given formula to find the size of file downloaded:

Size of file downloaded = r.t

Size of file downloaded = 800 kilobytes seconds \times 110 seconds =

<em>88000 kilobytes</em>.

Now, let us convert the unit kilobytes to megabytes to find the answer.

<em>Conversion formula:</em>

1000 kilobytes = 1 megabyte

Let us use unitary method to find the number of megabytes in 88000 kilobytes.

1 kilobytes = \frac{1}{1000} megabytes

88000 kilobytes = \frac{1}{1000} \times 88000 megabytes

\Rightarrow <em>88 megabytes.</em>

Therefore, the size of file downloaded is  <em>88 megabytes.</em>

5 0
3 years ago
Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
3 years ago
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