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podryga [215]
3 years ago
8

PEOPLE WHO BUY GOODS AND SERVICES ARE OF GROUP OF DECSION MAKERS CALLED?

Chemistry
1 answer:
Bumek [7]3 years ago
7 0
75% i think it is consumers
25% i think it is producer
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fig. 15 shows a simplified diagram of the electrolysis of a molten electrolyte containing lithium chloride. b. Describe how the
melisa1 [442]

During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.

<h3>What is electrolysis?</h3>

Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them.  In this process, the atoms and ions are interchanged by the addition or removal of electrons.

The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.

During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.

At anode :  2 Cl⁻ →    Cl₂ + 2e⁻

At cathode:   2 Li⁺   +   2e⁻  →  Li

Learn more about electrolysis, here:

brainly.com/question/12054569

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8 0
1 year ago
Looking at the name of an acid, how do you know if it only contains two elements or if it contains more than two?
Lisa [10]
Because it has two syllables
4 0
3 years ago
Read 2 more answers
Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound​
olga_2 [115]

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

Correct me if I'm wrong tnx:<

8 0
2 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
3 years ago
6th grade help me plzzzz
tiny-mole [99]

Answer:

positive

Explanation:

8 0
3 years ago
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