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AlekseyPX
3 years ago
5

For each of the following scenarios state whether H0 should be rejected or not. State any assumptions that you make beyond the i

nformation that is given.
(a) H0 : µ = 4, H1 : µ 6= 4, n = 15, X = 3.4, S = 1.5, α = .05.
(b) H0 : µ = 21, H1 : µ < 21, n = 75, X = 20.12, S = 2.1, α = .10.
(c) H0 : µ = 10, H1 : µ 6= 10, n = 36, p-value = 0.061.
Mathematics
1 answer:
scoundrel [369]3 years ago
7 0

Answer:

a)H_0 :\mu = 4\\ H_1 : \mu \neq 4 , n = 15 , X=3.4 , S=1.5 , α = .05

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{3.4-4}{\frac{1.5}{\sqrt{15}}}

t =-1.549

p- value = 0.607(using calculator)

α = .05

p- value > α

So, we failed to reject null hypothesis

b)H_0 :\mu = 21\\ H_1 : \mu < 21 , n =75 , X=20.12 , S=2.1 , α = .10

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{20.12-21}{\frac{2.1}{\sqrt{75}}}

t =-3.6290

p- value = 0.000412(using calculator)

α = .1

p- value< α

So, we reject null hypothesis

(c) H_0 :\mu = 10\\ H_1 : \mu \neq 10, n = 36, p-value = 0.061.

Assume α = .05

p-value = 0.061.

p- value > α

So, we failed to reject null hypothesis

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<h3>Answer: Choice B) x = 65, y = 10</h3>

====================================================

Work Shown:

The upper pair of angles 60 degrees and (2x-y) degrees are supplementary angles. This is because of the parallel lines. Note how they are same side interior angles. Therefore, (2x-y) and 60 combine to 180 degrees like so

(2x-y)+60 = 180

2x-y = 180-60 ... subtract 60 from both sides

2x-y = 120 ... call this equation 1

-------

Similarly, (2x+y) and 40 also combine to 180

(2x+y) + 40 = 180

2x+y = 180-40 ... subtract 40 from both sides

2x+y = 140 ... call this equation 2

------

Line up equation 1 and equation 2. Then add straight down

\ \ \  2x-y = 120\\+ 2x+y = 140\\\hrule\\\\\\ \ \ \ 4x+0y = 260\\\\

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If x = 65, then,

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y = 10

----------

Either way end up with x = 65 and y = 10

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