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Zinaida [17]
3 years ago
11

Explain how to write a composite function to find the area of the region at time t.

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer:

The composite function is:a(r(t)) = π (0.5 + 2t)²After simplification it becomes:a(r(t)) = π (0.25 + 2t + 4t²)Step-by-step explanation:Here is the complete function:a circular oil spill continues to increase in size. the radius of the oil spill, in miles, is given by the function r(t) = 0.5 + 2t, where t is the time in hours. the area of the circular region is given by the function a(r) = πr², where r is the radius of the circle at time t.  Explain how to write a composite function to find the area of the region at time t.Solution:The composite function is written by applying one function to another. The requirement of this question is to write a composite function to find are of region at time t.Leta(r) = πr²is function 1andr(t) = 0.5 + 2tis function 2ThenThis means that function r(t) should be applied to a(r) and it should be inside function a(r)Then composite function becomes:a(r(t))Now put the value of r(t) = 0.5 + 2t into a(r) = πr²a(r(t)) = π (0.5 + 2t)²So this is the composite function to find area of the region at time tSimplifying this equation we get:a(r(t)) = π (0.5 + 2t)²        = π (0.5 + 2t) (0.5 + 2t)       =  π [(0.5 * 0.5)+ (0.5 * 2t) + (2t * 0.5) + (2t *2t)]       = π (0.25 + 1t +  1t + 4t²)       = π ( 0.25 + t + t + 4t²)       = π (0.25 + 2t + 4t²)a(r(t)) = π (0.25 + 2t + 4t²)

Step-by-step explanation:

Hope it helps you ✌️

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Answer:

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Explanation:

<u />

<u>1. First find the density of your chain</u>

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<u />

<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>

Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.

Calling x the amount of gold, then the amount of other metals is 66.7 - x:

        \dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34

       19.3x+635.66-9.7x=889.778

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the length of a rectangular building is 6 feet less than 3 times t he width. The perimeter is 120 feet. Find the width and the l
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