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2 years ago

Solve the equation x2 + x = 12.

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

4 0

3x=12 -> x=4 ………………………

Otrada [13]2 years ago

3 0

please give brainliest

Let's solve your equation step-by-step.

x2+x=12

Step 1: Subtract 12 from both sides.

x2+x−12=12−12

x2+x−12=0

Step 2: Factor left side of equation.

(x−3)(x+4)=0

Step 3: Set factors equal to 0.

x−3=0 or x+4=0

x=3 or x=−4

Answer:

x=3 or x=−4

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Mkey [24]

Answer:

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Step-by-step explanation:

Use the slope formula $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Plug it in $\frac{16-2}{61-0}$

Simplify $\frac{14}{61}$

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3 years ago

nevsk [136]

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2 years ago

Can anyone help please?

eduard

Answer:

2x+y=5.

Step-by-step explanation:

slope(m)=-2

passed through point (0,5)=(x1,y1)

then

the equation is

(y-y1)=m(x-x1)

or (y-5)=-2(x-0)

or (y-5)=-2x

or 2x+y=5 is the equation.

4 0

2 years ago

Question: 69 = 9r -3<br> r =

In-s [12.5K]

Answer:

8 = r

Step-by-step explanation:

69 = 9r -3

Add 3 to each side

69+3 = 9r -3+3

72 = 9r

Divide each side by 9

72 / 9 = 9r/9

8 = r

4 0

2 years ago

Read 2 more answers

Find three consecutive ODD integers such that the sum of 7 times the smallest and twice the largest is -91. Name the smallest in

Illusion [34]

Answer:

<h3> -11, -9, -7</h3><h3>the smallest: 2x+1 = -11</h3>

Step-by-step explanation:

{z - some integer}

2z+1 - the smallest number

7(2z+1) - <u>seven times the smallest number</u>

2z+1+2=2z+3 - the middle number

2z+3+2 = 2z+5 - the largest number

2(2z+5) - <u>twice the largest number</u>

7(2z+1) + 2(2z+5) - the sum of 7 times the smallest and twice the largest

7(2z+1) + 2(2z+5) = -91

14z + 7 + 4z + 10 = -91

-17 -17

18z = -108

÷18 ÷18

z = -6

2z+1 = 2(-6)+1 = -12 + 1 = -11

2z+3 = 2(-6)+3 = -12 + 3 = -9

2z+5 = 2(-6)+5 = -12 + 5 = -7

5 0

3 years ago