3
correct me if im wrongg!!!
Answer: y + 7 = -2/3 (x - 1 )
Step-by-step explanation:
The equation of a line in point - slope form is given as :
= m(
)
Where m is the slope and (
,
) is the given point
substituting the values into the formula , we have:
y - (-7) = -2/3 ( x - 1)
y + 7 = -2/3(x - 1 )
Coordinates when you see t
13 quarters = 13 *0.25 = 3.25
3.60 - 3.25 = 0.35
0.35 = 0.25 +0.10
he has 1 dime and 14 quarters
Answer is B
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J