All categories

2 years ago

Hard problems that equal 1

1 answer:

6 0

10(10x1)-3x33
steps: you do the brackets first which is: 10x1 which equals 10, then using Bidmas you do 10x10 which is 100. then you do 100-3x33 which is 100-99 and that equals 1

You might be interested in

Question 1 (Multiple Choice Worth 5 points)

katrin [286]

Uurcrcucrvurctuccecuwxrve

5 0

3 years ago

a survey was done and a company found that 492 out of 500 batteries were good if 6000 batteries were produced how many would be

Tems11 [23]

This is a ratio based question.

$\frac{492}{500} = \frac{x}{6000}$
$x = 6000 \times \frac{492}{500}$

6 0

3 years ago

5) Vanessa and Javier each signed up for new gym memberships. Vanessa pays a monthly fee of $25 and

tamaranim1 [39]

Answer: 6.5 and 6

Step-by-step explanation:

3 0

2 years ago

If f(x) is continuous on a closed interval, then it is enough to look at the points where f prime (x )equals0 in order to find

aivan3 [116]

This would be false

5 0

2 years ago

A chain of retail computer stores opened 2 stores in its first year of operation. After 8 years of operation, the chain consiste

Helen [10]

Answer:

0.66

Step-by-step explanation:

The exponential growth equation is expressed as;

S(t) = S0e^kt

S(t) is the number of stores after t years

S0 is the initial number of stores

If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;

2 = S0e^k(1)

2 = S0e^k .... 1

Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;

206 = S0e^k(1)

206 = S0e^8k .... 2

Next is to calculate the value of k

Divide equation 2 by 1;

$\frac{206}{2} = \frac{S0e^{8k} }{S0e^k }\\103 = e^{7k}\\apply \ ln \ to \ both \ sides\\ln103 = lne^{7k}\\ln103 = 7k\\k = \frac{ln103}{7}\\k = \frac{4.6347}{7} \\k = 0.6621$

Hence the value of k to the nearest hundredth is 0.66

4 0

2 years ago