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ratelena [41]
3 years ago
13

BRAINLIEST ANSWER AND 30 PTS

Advanced Placement (AP)
1 answer:
Anestetic [448]3 years ago
4 0
I believe it would be the letter 'C' ;w; Good luck, sorry if this is incorrect. 
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The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D

3) lim sin(2x)/x when x →0
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 Derivative x→ 1
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 and lim sin(2x)/x when x →0 is 2

4) lim(sinx)/(2x²-x)

→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1

and so on and so forth. Try to continue following the same principle


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Question 13 (1 point)
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