Okay to find the perpendicular bisector of a segment you first need to find the slope of the reference segment.
m=(y2-y1)/(x2-x1) in this case:
m=(-5-1)/(2-4)
m=-6/-2
m=3
Now for the the bisector line to be perpendicular its slope must be the negative reciprocal of the reference segment, mathematically:
m1*m2=-1 in this case:
3m=-1
m=-1/3
So now we know that the slope is -1/3 we need to find the midpoint of the line segment that we are bisecting. The midpoint is simply the average of the coordinates of the endpoints, mathematically:
mp=((x1+x2)/2, (y1+y2)/2), in this case:
mp=((4+2)/2, (1-5)/2)
mp=(6/2, -4/2)
mp=(3,-2)
So our bisector must pass through the midpoint, or (3,-2) and have a slope of -1/3 so we can say:
y=mx+b, where m=slope and b=y-intercept, and given what we know:
-2=(-1/3)3+b
-2=-3/3+b
-2=-1+b
-1=b
So now we have the complete equation of the perpendicular bisector...
y=-x/3-1 or more neatly in my opinion :P
y=(-x-3)/3
4,760 and then if there’s a unit of measurement
Answer:
126
Step-by-step explanation:
360 x 35%= 126
360 x 0.35 = 126
Answer:
X=9 and X=5
Step-by-step explanation:
So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.
X^2 - 14X +45 = 0
Now you can factor. Your looking for two factors that equal 45 and add to -14
All factors of 45:
1 and 45, 3 and 15, 5 and 9, -1 and -45,
-3 and -15, -5 and -9
So out of those combinations -5 and -9 both multiply to 45 and add up to -14 so these are our common factors
(X-5)(X-9)=0
X-5=0 add 5 to both sides X=5
X-9=0 add 9 to both sides X=9
