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Stella [2.4K]
3 years ago
7

Help its due rn plzzz

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

x  =  2.65, -2.65

Step-by-step explanation:

x² = 7

x = ± \sqrt{7}

or x  =  2.64575131.., -2.64575131...

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aivan3 [116]
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7 0
3 years ago
If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=8/17and cos b=1
n200080 [17]

Recall the sum identity for cosine:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

so that

cos(a + b) = 12/13 cos(a) - 8/17 sin(b)

Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,

cos²(a) + sin²(a) = 1   ⇒   cos(a) = √(1 - sin²(a)) = 15/17

cos²(b) + sin²(b) = 1   ⇒   sin(b) = √(1 - cos²(b)) = 5/13

Then

cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221

6 0
2 years ago
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vova2212 [387]

Answer:

5 pints of oil for 8 dollars

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3 0
3 years ago
Write a linear equation from the graph.
USPshnik [31]

Answer:

x+y=4...........eq1

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7 0
3 years ago
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