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Zinaida [17]
2 years ago
5

This relationship is given by the equation, v = gt. In this equation, g is the acceleration due to gravity, t is the number of s

econds, and v is the velocity of the falling object. Note that g is a constant.
Find and interpret the meaning of the initial value and the rate of change in this context

A. The initial value is 9.8. That means that object’s initial velocity 9.8 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
B. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 98. That means the acceleration due to gravity is 98.0 m/s2.
C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
D. The initial value is 9.8. That means that object’s initial velocity 9.8 m/s. The rate of change is 0.98. That means the acceleration due to gravity is 0.98 m/s2.
Mathematics
1 answer:
DENIUS [597]2 years ago
4 0

v=gt,

Initial value when time t=0, v=g*0=0.

t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.

v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.

Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².

Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.

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Given the equation P2 = A3, what is the orbital period, in years, for the planet Saturn? (Saturn is located 9.5 AU from the sun.
algol [13]

Answer: 29.28 years

Explanation:

From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body  it is revolving about.

P² =A³

Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)

It is given that, For Saturn, A = 9.5 AU. We need to find P

⇒P² = (9.5 AU)³

⇒P² = 857.38

⇒P = 29.28 years

Thus, the orbital period of Jupiter is 29.28 years around the Sun.

5 0
3 years ago
Use the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. Scale factor= 3 in:2m.
podryga [215]

Given:

The side of square = 12 in.

Scale factor of enlargement = 3 in : 2 m

To find:

The proportion that is use to solve the side length, x, of the enlarged square.

Solution:

Let, the side of length of enlarged square = x m

In case of enlargement the corresponding sides are proportional.

\dfrac{3}{12}=\dfrac{2}{x}

3x=2\times 12

3x=24

Divide both sides by 3.

x=\dfrac{24}{3}

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4 0
2 years ago
Please help work this equation
Flauer [41]

Hi!

<u>Given these two equations:</u>

x = y + 8

x + 4 = 2(y + 4)

We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:

(y+8)+4=2(y+4)

Combine like terms on both sides:

y+12=2y+8

Subtract y from both sides:

12=y+8

Subtract 8 from both sides:

y=4

Now, we can simply plug the y value in to the first equation, and solve for x:

x=4+8

Simplify:

x=12

<h3>Therefore, x is equal to 12 and y is equal to 4.</h3>

<u>Learn more about the substitution (and also elimination!) method here:</u>

brainly.com/question/14619835

4 0
2 years ago
One of the factors of 4x^2-9 is<br> (1)x+3<br> (2)2x+3<br> (3)4x-3<br> (4)x-3
slava [35]

Answer:

2x+3

Step-by-step explanation:

4x^2-9=(2x)^2 -3^2=(2x-3)(2x+3)

8 0
2 years ago
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Nataly [62]

Answer:

Step-by-step explanation:

the first one is correct

6 0
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