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3 years ago

Please help im on dead line

Mathematics

1 answer:

Serjik [45]3 years ago

8 0

Answer: C

Step-by-step explanation:

It is C because you are adding money to something you already have, hence positive integer

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I need to figure out how many solutions does the system of equations below have.

Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

$\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}$

$\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8$

$\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}$

$\frac{5x}{63} = \frac{82}{9}$

$45x = 63*82$

Both a and b are different of 0, so the system has one solution.

6 0

3 years ago

Help asap :c T-T i tried!!!!

Sav [38]

The correct answer is A. 1

4 0

3 years ago

A road repair crew spread 7/8 of a ton of gravel evenly over 7 feet of road. How many tons of gravel did they spread on each foo

Alex

7/8 duh it there u just have to read it nicely

5 0

3 years ago

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago

The number of students in a school increased by 25%between last year and this year. Last year there were 250 students in the sch

alexandr1967 [171]

I think it's 275 sorry if I'm wrong

5 0

3 years ago

Read 2 more answers