9/11 is equal to 18/22, so then D.
Answer
15%
90%
2%
Explanation
Answer:
it is either the dice or the cups
Step-by-step explanation:
Answer: 0.0084
Step-by-step explanation:
Let p be the population proportion of the creatures in Wonderland are anthropomorphic animals.
As per given, p = 0.70
Sample size : n=120
Let
be the sample proportion of the creatures are anthropomorphic animals.
Now, required probability :
![P(\hat{p}>0.80)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.80-0.70}{\sqrt{\dfrac{0.70\times (1-0.70)}{120}}})\\\\P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.10}{\sqrt{\dfrac{0.70\times 30}{120}}})\\\\ =P(Z>\dfrac{0.10}{\sqrt{0.00175}})\ \ \ \ \ [Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\ =P(Z>\dfrac{0.10}{0.04183})\\\\\=P(Z>2.39)\\\\=1-P(Z\leq2.39)\\\\=1- 0.9916= 0.0084](https://tex.z-dn.net/?f=P%28%5Chat%7Bp%7D%3E0.80%29%3DP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.80-0.70%7D%7B%5Csqrt%7B%5Cdfrac%7B0.70%5Ctimes%20%281-0.70%29%7D%7B120%7D%7D%7D%29%5C%5C%5C%5CP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.10%7D%7B%5Csqrt%7B%5Cdfrac%7B0.70%5Ctimes%2030%7D%7B120%7D%7D%7D%29%5C%5C%5C%5C%20%3DP%28Z%3E%5Cdfrac%7B0.10%7D%7B%5Csqrt%7B0.00175%7D%7D%29%5C%20%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%20%3DP%28Z%3E%5Cdfrac%7B0.10%7D%7B0.04183%7D%29%5C%5C%5C%5C%5C%3DP%28Z%3E2.39%29%5C%5C%5C%5C%3D1-P%28Z%5Cleq2.39%29%5C%5C%5C%5C%3D1-%200.9916%3D%200.0084)
Hence, the probability that more than 80% of the sampled inhabitants are animals= 0.0084