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Umnica [9.8K]
3 years ago
8

Choose the graph where the constant of variation is 2.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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Please help thnk you.
Levart [38]
Hello!

You have to find what they multiplied to 18 to get 27

27 / 18 = 1.5

The multiplied the sides by 1.5 to get the second shape

6 * 1.5 = 9

The answer is C)9

Hope this helps!
7 0
3 years ago
Read 2 more answers
In my closet I have 12 pair of pants, 9 skirts, and 15 shirts. What is the ratio of 'shirts' to 'skirts and pants'?
vekshin1

Answer:

15:9

Step-by-step explanation:

Because you have a total of 15 shirts and a total of 9 skirts.

7 0
3 years ago
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What is 7 times the 6th power?
Sidana [21]
7^6 = 117,649
7 x 7 x 7 x 7 x 7 x 7 = 117,649
5 0
3 years ago
The base of a 13 foot ladder is 5 feet away from the wall. How far up the wall does the ladder reach?
frez [133]

let x be how far up the wall ladder reaches

by Pythagoras theorem

x^2+5^2=13^2

x^2 =(13^2)-(5^2)

x= square root of 144

x= 12 or x =-12(rej,x>0)

hence ladder reaches 12 foot up the wall

5 0
3 years ago
Read 2 more answers
In what follows use any of the following tests: Regression, multiple regression, one-sided t-test, or two-sided t-test. All conc
Yakvenalex [24]

Answer:

  1. Two sided  t-test ( d )
  2.  0.245782  ( c )
  3. Since P-value is too large we cannot conclude that the students’ weight are different for these two schools. ( c )
  4. The test is inconclusive; thus we cannot claim that the average weights are different. ( b )

Step-by-step explanation:

1)  Test performed is a Two sided test and this because we are trying to determine the mean difference between two groups irrespective of their direction

<u>2) Determine the P-value ( we will use a data-data analysis approach on excel data sheet while assuming Unequal variances )</u>

                               yes             No

Mean                   94.47059   89.76471

Variance              173.2647     95.19118

Observations            17            17

df                               30

t Stat                       1.184211  

P(T<=t) one-tail 0.122814  

t Critical one-tail 1.697261

P(T<=t) two-tail        0.245782

Hence The p-value =  0.245782

3) Since P-value is too large we cannot conclude that the students’ weight are different for these two schools.

4)   The test is inconclusive; thus we cannot claim that the average weights are different.

8 0
3 years ago
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