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Softa [21]
3 years ago
8

3-8 Present Value of Investments 165

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0
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3x²=12 extracting square roots​
ivann1987 [24]

Answer:

x = ± 2

Step-by-step explanation:

Given

3x² = 12 ( divide both sides by 3 )

x² = 4 ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

3 0
3 years ago
What type of arc is AB
stiv31 [10]

I'm sorry I don't know the answer but I do have to say that you are loved and no matter how many mistakes you make you will still always be loved.                        Step-by-step explanation:

3 0
2 years ago
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A statue is mounted on top of a 16 foot hill. From the base of the hill to where you are standing is 77 feet and the statue subt
DanielleElmas [232]

Consider right triangle with vertices B - base of the hill, S - top of the statue and Y - you. In this triangle angle B is right and angle Y is 13.2°. If h is a height of the statue, then the legs YB and BS have lengths 77 ft and 16+h ft.

You have lengths of two legs and measure of one acute angle, then you can use tangent to find h:

\tan 13.2^{\circ}=\dfrac{\text{opposite leg}}{\text{adjacent leg}} =\dfrac{16+h}{77}, \\ \\ 0.2345=\dfrac{16+h}{77},\\  \\ 16+h=0.2345\cdot 77=18.0565,\\ h=18.0565-16=2.0565 ft.

Answer: the height of the statue is 2.0565 ft.

8 0
2 years ago
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HELP PLZZZSS EASYYYY 10 POINTS *easy*
zalisa [80]

Answer:

A. 3:30.

Step-by-step explanation:

180 is 90+90 so that would put it in 3:30.

4 0
3 years ago
Which real numbers are zeros of the function?
monitta
<h3><u>The roots are -1/2, 0, 2, and 3.</u></h3>

Let's trying factoring this polynomial.

We can factor an x out of each term to start.

x(2x^3 - 9x^2 + 7x + 6)

We now know one of the roots is going to be zero.

Using the rational roots theorem, and the remainder theorem, we can try to find some more roots that way.

Factors of 6: 1, 2, 3, 6.

Factors of 2: 1

Possible rational roots: +/-1/2, +/-1, +/-2, +/-3/2, +/-3, +/-6

Using the remainder theorem, we can plug these values into the polynomial, and if we get a remainder of zero, we know it's a root.

-1/2(2(-1/2)^3 - 9(-1/2)^2 + 7(-1/2) + 6) = 0

Our first root is -1/2.

We can successfully factor a -1/2 out of this polynomial.

After diving the polynomial by -1/2, we're left with: 2x^2 - 10x + 12.

We can now try using the AC method to get our last two roots.

First, we can factor this polynomial to simplify it.

Divide all terms by 2.

2(x^2 - 5x + 6)

Now let's try using the AC method.

The digits -3 and -2 satisfy the criteria.

2(x - 3)(x - 2)

We now have all of our roots: 0, -1/2, 2, and 3.


6 0
3 years ago
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