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Softa [21]
3 years ago
8

3-8 Present Value of Investments 165

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0
Fulsfoucfcgipcguchocgyfyfy
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PLEASE HELP!!!!! I HAVE A DEADLINE !!!!
belka [17]

Answer:

V_rocket  = 44\pi  ft^3  = 138.2 ft^3

Step-by-step explanation:

Volume  of cone

V_cone = (1/3)*(\pi*(radius^2))*h

radius = 2ft

h = height of the cone = 3 ft

pi = 3.1416

V_cone = 4\pi  ft^3

Volume cylinder

V_cylin = (\pi*(radius^2))*h_cyl

h_cyl = height of the cylinder = 10 ft

V_cylin  = 40\pi  ft^3

Volume rocket

V_rocket = V_cone  +  V_cylin  = 4\pi  ft^3 + 40\pi  ft^3

V_rocket  = 44\pi  ft^3  = 138.2 ft^3

3 0
3 years ago
Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
  • (1 - sinθ)² / cos²θ

<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
  • secθ - tanθ
<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
  • (1 - cosθ)²/sin²θ

<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
  • 1/sinθ - cosθ / sinθ =
  • cosecθ - cotθ

<u>Sum of the results:</u>

  • cosecθ + cotθ + cosecθ - cotθ =
  • 2cosecθ
4 0
2 years ago
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Find the value of x and y.
Yanka [14]

Answer:

x = 13 \sqrt{3}  \\

y = 13

6 0
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Which graph represents the solution set of the inequality Negative 9 greater-than x?
Kamila [148]

Answer:

de answer is A

Step-by-step explanation:

hope i helped

7 0
3 years ago
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TiliK225 [7]
Answer— 45/15=3 so there is 3 classes with 15 students in each class? I didn’t really understand your question but I tried!

Hope it helped!
8 0
3 years ago
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