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Alex787 [66]
3 years ago
13

PLEASE HURRY WILL MARK BRAINLIEST 

Chemistry
2 answers:
Ket [755]3 years ago
7 0

Answer:

C. Combined number of neutrons and protons.

Explanation:

The number is the atomic mass. Atomic mass is neutrons + protons.

And I got it right on the quiz on E2020.

mr Goodwill [35]3 years ago
4 0

Answer:

12 Neutrons

1 Valence Electron

23 ions [11 Protons and 12 Neutrons]

22 ions [11 Electrons and Protons]

Explanation:

To find the number of neutrons in an element, you simply take its atomic number and deduct that from the atomic mass [<em>round</em><em> </em>if necessary]. There is one <em>valence </em><em>electron</em><em> </em>because<em> </em>according to the Periodic Table of Elements, the first three energy levels can fit 2 - 8 electrons:

1st Energy Level → 2 Electrons

2nd Energy Level → 8 Electrons

3rd Energy Level → 8 Electrons

4th Energy Level → 18 Electrons

5th Energy Level → 18 Electrons

6th Energy Level [Lanthanide Series] → 32 Electrons

7th Energy Level [Actinide Series] → 32 Electrons

So, as you can see, 2 + 8 gives you 10. So from there, we already filled up 2 energy levels. Now going to the third one will leave us with only one electron left over. That is where that valence electron is.

** I encourage you to write this down in your Chemistry notebook somewhere, so you can keep this stored in your memory at all times. There are some pointers in the answer as well. Copy that.

I am joyous to assist you anytime.

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Answer:

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Explanation:

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5 0
3 years ago
A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. How much calcium is contained in 40.0 g of c
Temka [501]

Answer:

20.53 g.

Explanation:

  • Knowing that every 15.0 g of pure calcium fluoride contains 7.70 g of calcium.

<u>Using cross multiplication:</u>

15.0 g of pure calcium fluoride contains → 7.70 g of calcium.

40.0 g of pure calcium fluoride contains → ??? g of calcium.

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6 0
3 years ago
How many moles are in 54 grams of C?
Serjik [45]
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8 0
3 years ago
Calculate the temperature required to make a 75.8 ml ballon initially at 57.9c change its value to 50.8ml
nika2105 [10]

Answer:

T₂ = 221.8 K

Explanation:

Given data:

Initial temperature = 57.9°C ( 57.9+273 =330.9 k)

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Final temperature = ?

Solution:

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V₁ /T₁= V₂/T₂

T₂ = V₂T₁/V₁

T₂ = 50.8 mL ×330.9 k / 75.8 mL

T₂ = 16809.72 mL.K/ 75.8 mL

T₂ = 221.8 K

6 0
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