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tankabanditka [31]
3 years ago
14

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6

×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K. Which of the following are true? Choose all that apply The sample is initially a gas. The liquid initially present will vaporize. The final state of the substance is a solid. One or more phase changes will occur. The final state of the substance is a liquid. Submit Answer
Chemistry
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

The true statements include;

- The sample is initially a gas.

- The final state of the substance is a solid.

- One or more phase changes will occur.

The untrue/false statements include;

- The liquid initially present will vaporize.

- The final state of the substance is a liquid.

Explanation:

A couple pieces of informatton on Fluorine is imitially provided.

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K

So, a question is now attached about a sample of Fluorine. A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K.

We are then told to examine a group of options to find the ones that are correct/apply.

Taking the options one at a time

- The sample is initially a gas.

The initial state of the Fluorine sample has its temperature at 90.3 K, which is above the gas' boiling point. Hence, the sample can be concluded to initially be a gas.

- The liquid initially present will vaporize.

The sample doesn't initially contain liquid. And even of it did, the temperature is cooled, not heated , Hence, this statement is wrong.

- The final state of the substance is a solid.

The sample of Fluorine moves from a temperature higher than boiling point (85.0 K), with the sample in gaseous form, to one that is at a lower temperature (49.3 K) than the gas' normal melting point (53.5 K).

At temperatures lower than melting point, a substance exists in the solid form. Hence, this statement is true. The final state of the substance is solid.

- One or more phase changes will occur.

In moving from 90.3 K to 49.3 K for the sample and passing through the substance's boiling and melting points (85.0 K and 53.5 K respectively) along the way, it is logical to conclude that there would be one or more phase changes will occur. This statement is true.

- The final state of the substance is a liquid.

This is false as we already established that the final state of the substance is a solid. Hence, this statement is false.

Hope this Helps!!!

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olga nikolaevna [1]
In order to understand what is the limiting reactant is useful to convert the masses of reactants into moles. The molecular masses are:

C_7H_6O_3 = 138\frac{g}{mol}\\ C_4H_6O_3 = 100\frac{g}{mol}

Converting masses into moles:

70\g \C_7H_6O_3\cdot \frac{1\ mol}{138\ g} = 0.5\ mol\ C_7H_6O_3

80\ g\ C_4H_6O_3\cdot \frac{1\ mol}{100\ g} = 0.8\ mol\ C_4H_6O_3

In the reaction, 2 moles of C_7H_6O_3 are necessary to react with 1 mol of C_4H_6O_3. Following this ratio:

0.8\ mol\ C_4H_6O_3\cdot \frac{2\ mol\ C_7H_6O_3}{1\ mol\ C_4H_6O_3} = 1.6\ mol\ C_7H_6O_3

We have only 0.5 mol of C_7H_6O_3, i.e, we don't have enough amount of salicylic acid, therefore, this is the limiting reactant.
3 0
3 years ago
Read 2 more answers
1. The density of solid Cu is 8.96g/cm3 . How many atoms are present per cubic centimeter(cm3) of Cu ?
Leni [432]

Answer:

8.5 × 10²² atom / cm³, 2.125 × 10²² unit cells / cm³, 4.7 × 10⁻²³ cm³ / cell unit, 3.61 × 10⁻⁸ cm /cell

Explanation:

The density of the solid Cu = 8.96 g/cm³

a) number of atoms present

mole = mass / molar mass = (8.96 g/cm³) / 63.546 = 0.141 mol

number of atoms = mole × avogadro's constant = 0.141 × 6.02 × 10²³ = 8.5 × 10²² atom / cm³

b) a face-centered cubic unit cell contains 4 atoms

8.5 × 10²² atom / cm³ / 4 = 2.125 × 10²² unit cells / cm³

c) the volume of a unit cell of the metal = reciprocal of  2.125 × 10²² unit cells / cm³  = 1 ÷ ( 2.125 × 10²² unit cells / cm³ ) = 4.7 × 10⁻²³ cm³ / cell unit

the edge length of a cell of cu = ∛(4.7 × 10⁻²³ cm³ / cell unit) = 3.61 × 10⁻⁸ cm /cell

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3 years ago
An organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classifie
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Answer:

c. alkyne.

Explanation:

Hello there!

In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.

In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.

Regards!

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Carbon and silicon are tetravalent but ge sn pb show di valency. Why
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<u>Answer:</u>

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That's because Ge, tin, and Pb show inert pair effect and has a greater nuclear effective charge on the 's' electrons due to poor shielding effect.  .That's why these elements are not able to share their valence electrons while carbon and silicon does and show "catenation" which is the ability to form long chain molecules.

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Answer:

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