Answer:0.55 i think
Step-by-step explanation:
Mean of a data = Sum of all observations ÷ Total number of observations
Mean of this data will be :
Sum of all observarions = 17 + 13 + 18 + 20 + 17 + 15 + 12 = 112
Total number of observations = 7
Mean = 112 ÷ 7
Mean = 16
Therefore the mean of this data set <em>=</em><em> </em><em>1</em><em>6</em><em> </em>
Easy peasy
remember that the arc is a part of the perimiter of the circle aka circumference
also 360 degrees=circle
we are given the radius
calculate circumference
c=2pi times r
r=14
c=pi times 2 itimes 14
c=28pi
100 degrees is the arc
find what fraction of the circumferece thei srepresents
whole=360
100/360=10/36=5/18
so if circumference=28pi then multiply 5/18 by that
5/18 times 28pi=140pi/18=70pi/9
legnth=(70pi)/9 cm
if you were to aprox pi to 3.14 then the answer would be
24.4222222 cm
Answer:
114 units²
Step-by-step explanation:
The opposite sides of a parallelogram are congruent, so
AB = CD , that is
13x - 7 = 5x + 9 ( subtract 5x from both sides )
8x - 7 = 9 ( add 7 to both sides )
8x = 16 ( divide both sides by 8 )
x = 2
Then
5x + 9 = 5(2) + 9 = 10 + 9 = 19
3x = 3(2) = 6
The area (A) of a parallelogram is calculated as
A = bh ( b is the base and h the perpendicular height ), thus
A = 19 × 6 = 114 units²
36 all together.
22 first
14 second
8 random chosen
A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29
Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)
B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29
Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)
C) 22/36
21/35
20/34
19/33
18/32
17/31
Multiply..
Probability.. 0.038306451612903
D) 14/36
13/35
12/34
11/33
X... p=0.016993464052288
Probably not correct, haven't done probability in years.
