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Virty [35]
3 years ago
11

How do you know how long a trip will take if you have 399 mileage on one tank of gas but the maximum you can drive in one day is

600?
Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

Step-by-step explanation:

600 minus 399 is 201

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6k^3+10k^2−56k and 5(7k−3)(3k−7)share a common binomial factor. What binomial factor do they share?
goldenfox [79]

Answer:

Step-by-step explanation:

6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)

common factor is 3k-7

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Find the value of x in 4:x::x:16
AnnyKZ [126]

Given:

4:x::x:16

To find:

The value of x.

Solution:

We have,

4:x::x:16

It means, we have

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It can be rewritten as

\dfrac{4}{x}=\dfrac{x}{16}

On cross multiplication, we get

4\times 16=x\times x

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Taking square root on both sides.

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4 0
3 years ago
Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.
galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

ut =  \sqrt{ {6}^{2}  +  {5}^{2} }   \\  \sqrt{36 + 25}  \\  \sqrt{61 }  \\ using \: cosine \: rule \\ cos \: u =  \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times  \sqrt{61} }  \\  \\  =  \frac{25 + 61 - 36}{78}  \\  \\  = \frac{50}{78 }  \\  \cos \: u = 0.64 \\ m \:u = 50.2

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3 years ago
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