Rectangle, triangle, and I believe square
Let
x = the number of shorts bought
y = the number of t-shirts bought
A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10 (1)
Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2 (2)
Graph the equations y = -1.6x + 10 and x = 2.
The shaded region satisfies both inequalities.
Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.
I would choose A
You can simply try every answer and see which one gives you 16a-24ab
Answer: slope= 6
Slope intercept equation= y= 6x +2
Step-by-step explanation:
Slope formula: (y2 - y1) ÷ (x2 - x1) > (-4-8) ÷ (-1-1) = -12/-2 or 6
Plug slope (-6) and one coordinate into point slope form: y-1=m (x-1)
where m is slope and (1,8) would be (x,y)
Y-8= 6(x-1) > y-8 = 5x -6 > y= 6x +2
Answer:
D. 1
Step-by-step explanation:
We have the expression, ![\frac{\csc^{2}x\sec^{2}x}{\sec^{2}x+\csc^{2}x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ccsc%5E%7B2%7Dx%5Csec%5E%7B2%7Dx%7D%7B%5Csec%5E%7B2%7Dx%2B%5Ccsc%5E%7B2%7Dx%7D)
We get, eliminating the cosecant function,
![\frac{\sec^{2}x}{\frac{\sec^{2}x}{\csc^{2}x}+1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5E%7B2%7Dx%7D%7B%5Cfrac%7B%5Csec%5E%7B2%7Dx%7D%7B%5Ccsc%5E%7B2%7Dx%7D%2B1%7D)
As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,
i.e. ![\frac{\sec^{2}x}{\frac{\sin^{2}x}{\cos^{2}x}+1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5E%7B2%7Dx%7D%7B%5Cfrac%7B%5Csin%5E%7B2%7Dx%7D%7B%5Ccos%5E%7B2%7Dx%7D%2B1%7D)
i.e. ![\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Ccos%5E%7B2%7Dx%7D%5Ctimes%20%5Cfrac%7B%5Ccos%5E%7B2%7Dx%7D%7B%5Csin%5E%7B2%7Dx%2B%5Ccos%5E%7B2%7Dx%7D)
Since, we know that, ![\sin^{2}x+\cos^{2}x=1](https://tex.z-dn.net/?f=%5Csin%5E%7B2%7Dx%2B%5Ccos%5E%7B2%7Dx%3D1)
Thus,
![\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}=1](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Ccos%5E%7B2%7Dx%7D%5Ctimes%20%5Cfrac%7B%5Ccos%5E%7B2%7Dx%7D%7B%5Csin%5E%7B2%7Dx%2B%5Ccos%5E%7B2%7Dx%7D%3D1)
So, after simplifying, we get that the result is 1.
Hence, option D is correct.