What is the slope of the line

97/20 as a mixed number

Paraphin [41]

4 17/20 is 97/20 as a mixed number.

3 0

2 years ago

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Hello pls help with this

lutik1710 [3]

Answer:

C

Step-by-step explanation:

7 0

2 years ago

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A 4 cm × 6 cm 4cm×6cmstart color #1fab54, 4, start text, c, m, end text, times, 6, start text, c, m, end text, end color #1f

Andreas93 [3]

Answer:

Area of the rectangle: 24 cm²
Area of the circle: 380.13 cm²
Area of between the circle and the rectangle: 356.13 cm²

Explanation:

The question describes a rectangle of dimensions 4 cm × 6 cm inscribed in a circle with radius 11 cm.

You can find:

The area of the rectangle
The area of the circle
The area between the rectangle and the circle.

1. Area of the rectangle:

$Area=length\times width=4cm\times 6cm=24cm^2$

2. Area of the circle:

$Area=\pi\times radius^2=\pi \times (11cm)^2\approx 380.13cm^2$

3. Area between the rectangle of the circle:

This is the area of the circle that does not belong to (or is outside of) the area of the rectangle.

$Area=\text{area of the circle - area of the rectangle}\\ \\ Area=380.13cm^2-24cm^2=356.13cm^2$

8 0

2 years ago

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The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16

dusya [7]

Answer:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

$n_1 = 16$ represent the sampe size 1

$n_2 =16$ represent the sample 2

$s^2_1 = 2.5$ represent the sample deviation for 1

$s^2_2 = 5.5$ represent the sample variance for 2

$\alpha=0.10$ represent the significance level provided

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \neq \sigma^2_2$

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

5 0

3 years ago

A microscope shows an image of an object that is 40 times the object's actual size. So, the

Olenka [21]

Answer:

I don't know I wanna say the 3rd one

Step-by-step explanation:

4 0

2 years ago