Solve this linear equation for p.
2 answers:
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<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Answer: x= Makes It True
Explantion: step 1: simplify both sides of the equation. −5x−(−7−4x)=−2(3x−4) −5x+−1(−7−4x)=−2(3x−4)(distribute the negative sign) −5x+(−1)(−7)+−1(−4x)=−2(3x−4) −5x+7+4x=−2(3x−4) −5x+7+4x=(−2)(3x)+(−2)(−4)(distribute) −5x+7+4x=−6x+8 (−5x+4x)+(7)=−6x+8(combine like terms) −x+7=−6x+8 −x+7=−6x+8 step 2: add 6x to both sides. −x+7+6x=−6x+8+6x 5x+7=8 step 3: subtract 7 from both sides. 5x+7−7=8−7 5x=1
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