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Mrrafil [7]
3 years ago
7

Identify the slope and y-intercept of y = -x +1

Mathematics
2 answers:
Brrunno [24]3 years ago
4 0
The slope is -1 because the number beside x is always the slope and the y-intercept is 1 because the number being added or subtracted from x is always the y intercept
Rina8888 [55]3 years ago
3 0
<u>Slope</u>
y = -x + 1
The slope of the equation is equal to -1.

<u>Y - Intercept</u>
y = -x + 1
y = -0 + 1
y = 0 + 1
y = 1

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What number is 150% of 92
Setler79 [48]
The answer is 138 because 92 * 150= 13,900 and 1*100= 100.
Then you divide 13,800 by 100 and get 138.

So the answer is 138.

Hope that helped. :) :0 :p :D :d

6 0
3 years ago
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What is the first step in solving the equation?<br><br> 14 = -2m
ollegr [7]

Answer:

first you need to divide each side by -2

Step-by-step explanation:

start with dividing by -2, then you are left with -7 = m which is the answer.

7 0
2 years ago
How do you solve 3x+7=x
vredina [299]
3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: \frac{7}{-2} = x
Fourth, simplify \frac{7}{-2} to -\frac{7}{2} / Your problem should look like: - \frac{7}{2} = x
Fifth, switch sides. / Your problem should look like: x = -\frac{7}{2}

Answer as fraction: -\frac{7}{2}
Answer as decimal: -3.5


8 0
3 years ago
Read 2 more answers
Fifty pro-football rookies were rated on a scale of 1 to 5, based on performance at a training camp as well as on past performan
son4ous [18]

Answer:

(a-1) 22 rookies receiving a rating of 4 or better.

(a-2) 14 rookies received a rating of 2 or worse.

(b-1) Constructed below in explanation.

(b-2) 8% of total rookies received a rating of 5.

Step-by-step explanation:

We are provided the rating of Fifty pro-football rookies on a scale of 1 to 5 based on performance at a training camp as well as on past performance.

The frequency distribution constructed is given below:

 Rating          Frequency

     1                       4

     2                     10       where ranking of 1 indicate a poor prospect whereas

     3                     14         ranking of 5 indicate an excellent prospect.

     4                     18

     5                      4

(a-1) Rookies receiving a rating of 4 or better = Rating of 4 + Rating of 5

       So, by seeing the frequency distribution 18 rookies received a rating of

         4 and 4 rookies received a rating of 5.

Hence, Rookies receiving a rating of 4 or better = 18 + 4 = 22 rookies.

(a-2) Number of rookies received a rating of 2 or worse = Rating of 2 +

                                                                                                 Rating of 1

     So, by seeing the frequency distribution 10 rookies received a rating of

      2 and 4 rookies received a rating of 1.

Hence, Rookies receiving a rating of 2 or worse = 10 + 4 = 14 rookies.

(b-1) Relative Frequency is calculated as = Each frequency value /

                                                                         Total Frequency

   Rating        Frequency(f)        Relative Frequency

     1                       4                          4 / 50 = 0.08

     2                     10                         10 / 50 = 0.2

     3                     14                          14 / 50 = 0.28

     4                     18                          18 / 50 = 0.36

     5                   <u>   4    </u>                       4 / 50  = 0.08

                     \sum f<u>= 50 </u>                

Hence, this is the required relative frequency distribution.

(b-2) To calculate what percent received a rating of 5 is given by equation :

            <em>  x% of 50 = 4 </em> {Here 4 because 4 rookies received rating of 5}

         x = \frac{4*100}{50} = 8% .

Therefore, 8% of total rookies received a rating of 5.

5 0
3 years ago
Suppose that we have two identical boxes: box 1 and box 2. box 1 contains 5 red balls and 3 blue balls. box 2 contains 2 red bal
sineoko [7]

(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.

... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)

... P(blue) = 25/48 . . . . probability the ball is blue

(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)

... = ((3/8)·(1/2))/(25/48)

... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1

8 0
3 years ago
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