I switched both sides of the equation in the very beginning so it would be easier to solve.
<u>Answer:</u>
The number of tickets bought is 1000 adults tickets and 700 children were present
<u>Explanation:</u>
Let the number of children and adults present in the circus be x and y respectively
According to question,
Then, x + y = 1700 ……………..equation (1)
And, cost of ticket to circus for children and adult be 19, 42 respectively
Total cost of ticket;
for adults = 42y; for children = 19x
19x + 42y = 55300 …………………equation (2)
Multiplying equation (1) by 19
19x + 19y = 32300 ……………… eqn (3)
Subtracting equation 1 and 3, we get
23y = 23000
y = 1000
putting this value in eq (1), we get x = 700
Therefore, 1000 adults and 700 children were present
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Answer:
I hope this helps a little bit
Answer
73
Step-by-step explanation:
you need to subtract the 26 from 120 to get 94 divide that by 2 to get 47 so thats haw many calls they each made then add on the 26 to find her amount to get 73
M(CE) = 78 + 78*4/26 = 90
