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qaws [65]
2 years ago
6

∠ABC is a 40∘ angle. Point A is at (7, 1) Point B is at (3, 2) Point C is at (8, -1) If ∠ABC is rotated 180∘ about the origin, w

hat are the new points on the image and what is the new angle degree measurement?
Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
8 0

Answer:

The new points would be (-7, -1), (-3, -2) and (-8, 1). The angle would not change

Step-by-step explanation:

When you rotate points by 180 degrees, you simply change the sign on the ordered pairs. This will give you the new points.

Also, spinning the points will not change the angle between them. Therefore it stays the same.

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Answer:

The solutions are:

x=2

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Explanation:

2x2+3x−10=0

hope this helps (:

Step-by-step explanation:

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If the measure of &lt; A is 99 ° and the measure of &lt; B is 81 ° , then &lt; A and &lt; B are _____.
Doss [256]

Answer:

D.supplementary angles

Step-by-step explanation:

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3 years ago
Read 2 more answers
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d
skelet666 [1.2K]

Answer:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(30,7.8)  

Where \mu=30 and \sigma=7.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.80   (a)

P(X   (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

8 0
3 years ago
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