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svlad2 [7]
3 years ago
5

A square rug has an inner square in the center. The side length of the inner square is x inches and the width of the outer regio

n is 4 in. What is the area of the outer part of the​ rug?
Mathematics
1 answer:
Gwar [14]3 years ago
6 0

Answer: area of the outer part of the​ rug= 16 -x²

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a square: Side²

Since the area of the rug including the inner square is:  

Area of the rug = 4² =16 in²

And the area of the inner square is equal to:

Area if the inner square = x²

To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.

Area of the outer part of the rug= 16 -x²

Feel free to ask for more if needed or if you did not understand something.

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When x^3 + kx^2 − 4x + 2 is divided by x + 2 the remainder is 26, find k.
Elis [28]

Answer:

k = 6

Step-by-step explanation:

3 0
3 years ago
1. Given f(x) =1/4 (x – 8), what is the value of f(24)?
goldenfox [79]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

f(24)=4

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

f(x)=\frac{1}{4}(x-8)\\-----------\\\rightarrow f(24)= \frac{1}{4}(24-8)\\\\\rightarrow f(24) = \frac{1}{4}( 16)\\\\\rightarrow\boxed{f(24)=4}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

8 0
3 years ago
Read 2 more answers
If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

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