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3 years ago

I need help with this question someone please help me

Physics

1 answer:

neonofarm [45]3 years ago

4 0

Sadly, I can't remember the name of who's 'Law' this is
in Electricity and Magnetism, but it says that the net
flux passing through a closed surface is equal to the
net charge inside.

In the picture, the net charge inside the surface is ( + q - q ) = Zero.

So it must follow, as the night follows the day, the net flux
through the surface is Zero. (D)

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3 years ago

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1. Why should you use scientific notation when writing big numbers?

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3 years ago

PLEASE SOLVE QUICKLY!!!<br> Solve for A, B, and C from graph

hram777 [196]

A = 59.35cm

B = 196.56g

C = 74.65g

<u>Explanation:</u>

We know,

$x = \frac{L}{\frac{W}{F} +1}$

and L = x+y

Total length, L = 100cm

Weight of Beam, W = 71.8g

Center of mass, x = 49.2cm

Added weight, F = 240g

Position weight placed from fulcrum, y = ?

$L-y = \frac{L}{\frac{W}{F}+1 } \\100 - y = \frac{100}{\frac{71.8}{49.2}+1 } \\100 - y = \frac{100}{1.46+1}\\\\100 - y = \frac{100}{2.46} \\100-y = 40.65\\\\y = 59.35cm$

Therefore, position weight placed from fulcrum is 59.35cm

Total length, L = 100cm

Center of mass, x = 47.8 cm

Added weight, F = 180g

Position weight placed from fulcrum, y = 12.4cm

Weight of Beam, W = ?

$47.8 = \frac{100}{\frac{W}{180}+1 }\\\47.8 = \frac{100}{\frac{W+180}{180} } \\\\47.8 = \frac{100 X 180}{W+180}\\ \\47.8W + 47.8 X 180 = 18000\\47.8W = 18000 - 8604\\W = \frac{9396}{47.8}\\ W = 196.56g$

Therefore, weight of the beam is 196.56g

Total length, L = 100cm

Center of mass, x = 50.8 cm

Position weight placed from fulcrum, y = 9.8cm

Weight of Beam, W = 72.3g

Added weight, F = ?

$50.8 = \frac{100}{\frac{72.3}{F}+1 }\\\ 50.8 = \frac{100}{\frac{72.3+F}{F} } \\\\50.8 = \frac{100 X F}{72.3+F}\\ \\50.8 X 72.3 + 50.8 X F = 100F\\\\3672.84 = 100F-50.8F\\3672.84 = 49.2F\\F = 74.65g$

Therefore, Added weight F is 74.65g

A = 59.35cm

B = 196.56g

C = 74.65g

4 0

3 years ago

What is the magnitude of the average force required to stop an 1200 kg car in 9.0 s if the car is traveling at 80 km/h ? Express

Nutka1998 [239]

Answer: 2960N

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According to newtons first law of motion, force = mass × acceleration

To get acceleration,

Acceleration = velocity/time

Velocity = 80km/hr

Converting the velocity to m/s

80×1000/1×3600

velocity = 22.2m/s

Time = 9secs

Acceleration=22.2/9

Acceleration = 2.47m/s²

The get the force

F= 1200×2.47

F = 2960N

3 0

3 years ago