Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
Answer:
-12.38 N
Explanation:
This question requires you to first find the acceleration then apply Newton's 2nd law of motion to find the force.
To find deceleration use the formula;
v²= u²+2ad ---where
v= final speed = 0 m/s
u= initial speed = 3.0 m/s
a= acceleration { in this case , deceleration} = ?
d= distance from the point where its passenger rolled off= 4.0 m
therefore ;
Mass of the sled is calculated from its weight force.
Weight force = mg
mass of sled = weight force / g where g= 10 m/s²
mass of sled = 110/10 = 11kg
The magnitude of horizontal net force will be : F= ma where ;
m= mass of sled = 11 kg
a= deceleration = -9/8 m/s²
F = 11 * -9/8 = -12.38 N
Force is acting on the opposite direction of the initial motion of the sled.
I hope this helps you out!
The part of the question that says " x 10⁶ " means
" move the decimal point 6 places that way ===> ".
So take the 1.986 and do that to it.
If there aren't enough places to move the decimal point far enough,
add some zeros to the 1.986 before you move the point.
Answer:
its all black I cant see the image can you re upload it
Explanation: