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Leokris [45]
3 years ago
11

Pls help me !!! <3333

Physics
2 answers:
borishaifa [10]3 years ago
8 0

Answer:

1. Is a different pitch, has a different speed

2. is brighter or dimmer, has a different energy

Explanation:

Ira Lisetskai [31]3 years ago
3 0

Answer:

1. A. is louder or softer

2. B. Has a different speed

Explanation:

Sorry if any or both are wrong

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He discovered gravity. He found that there was a force keeping everything on earth from floating up and away.
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What is a gear. Please give detailed explanation
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Alberto is walking east at 10 m/s from his house to his grandma's house. It takes him 30s to walk 50 m/s more to his grandma's h
Pachacha [2.7K]

Answer:

Acceleration = 1.33m/s² East

Explanation:

Given the following data;

Initial velocity = 10m/s

Final velocity = 50m/s

Time = 30secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

a = \frac{50 - 10}{30}

a = \frac{40}{30}

Acceleration = 1.33m/s² East

3 0
3 years ago
Can someone please here me I’m confused
Naddika [18.5K]
I would say z, x, y, w
5 0
4 years ago
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.
noname [10]

Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

Explanation:

From the question we are told that

   The radius of the inner conductor  is  r_1 = 1 \ mm =  0.001 \ m

    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

    The potential at the outer conductor is  V = 1.5 kV  =  1.5 *10^{3} \  V

Generally the capacitance per length of the capacitor like set up of the two conductors is

      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

Here \epsilon_o is the permitivity of free space with value  \epsilon_o =  8.85*10^{-12} C/(V \cdot m)

=>   C= \frac{2 *  3.142  * 8.85*10^{-12}  }{ ln [\frac{0.003}{0.001} ]}

=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

      \rho_l  =  C *  V

=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

3 0
3 years ago
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