<h3><u>Answer;</u></h3>
Electron cloud
<h3><u>Explanation;</u></h3>
- <em><u>An atom is the smallest particle of an element that can take part in a chemical reaction. Atom is made up of two parts ; that is the nucleus and the electron cloud. The nucleus contain subatomic particles; protons and neutrons, while the electron cloud contains the electrons.</u></em>
- <em><u>The electron cloud is the largest part of the atom and is mostly an empty space. Most of an atom is a cloud of electrons surrounding a space called the nucleus with tiny protons and neutrons.</u></em>
Answer:The term atomic number, conventionally denoted by the symbol Z, indicates number of protons present in the nucleus of an atom, which is also equal to the number of electrons in an uncharged atom. The number of neutrons is represented by the neutron number (N)
Explanation:
Answer:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
Explanation:
Question
Assuming this question "Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, except when the symbol is needed to make your meaning clear. For example, 1*10^5 is not the same as 110^5 . When you need to be explicit, type * (Shift + 8) to insert the multiplication operator. You will see a multiplication dot (⋅) appear in the answer box. Do not use the symbol x. For example, for the expression ma,
typing m⋅a would be correct, but mxa would be incorrect".
Solution to the problem
For this case we want to write a expression for ma, and based on the previous info we can write:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
But is not correct do this:
mxa=mxa
axm = mxa
- Coefficient of static friction = 0.5
- Coefficient of Kinetic friction = 0.3
- Angular velocity = 500 RPMs
<h3>The Radius of the System</h3>
Let R be the radius of cylinder

The angular velocity is 500 RPMs

The normal force

Since the radius is very little for two block to execute circular motion so system will slide down.
Learn more on coefficient of static friction here;
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