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PIT_PIT [208]
3 years ago
10

one x-intercept for a parabola is at the point (1,0). Use the factor method to find the other x-intercept for the parabola defin

ed by this equation: y=4x^2+4x-8
Mathematics
2 answers:
mote1985 [20]3 years ago
7 0

Answer:(-2,0)


Step-by-step explanation:


viktelen [127]3 years ago
3 0

Answer:

4x^2 + 4x - 8 = 4*(x^2 + x - 2)

(x - 1) * (x - a) = x^2 + x - 2 --> a = -2


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To pass the time on his travels, Ibn Battuta decides to run a test to see if the mean caravan size passing through a certain out
Gemiola [76]

Answer:

C. He should run a T-test, and approximating it with a normal distribution would be inappropriate.

Step-by-step explanation:

We are told that the standard deviation is unknown.

Now in statistics, when we know the standard deviation, then we use a Z-test but when we don't know the standard deviation, then we will use a t-test.

Now, the t-test assumes a normal distribution for difference in mean of samples but it doesn't assume so for population.

Thus, we will run a t-test and doesn't need to approximate with a normal distribution.

8 0
3 years ago
A car company says that the mean gas mileage for its luxury sedan is at least 24 miles per gallon​ (mpg). You believe the claim
Anastaziya [24]

Answer:

t=\frac{23-24}{\frac{5}{\sqrt{5}}}=-0.447    

p_v =P(t_{(4)}  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't reject the claim that the true mean is at least 24 mpg (null hypothesis) at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

s=5 represent the sample standard deviation for the sample  

n=5 sample size  

\mu_o =24 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 24 (rejecting the claim proposed), the system of hypothesis would be:

Null hypothesis:\mu \geq 24  

Alternative hypothesis:\mu < 24  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{23-24}{\frac{5}{\sqrt{5}}}=-0.447    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=5-1=4  

Since is a one sided test the p value would be:  

p_v =P(t_{(4)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't reject the claim that the true mean is at least 24 mpg at 1% of signficance.  

5 0
3 years ago
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gizmo_the_mogwai [7]
To answer this question correctly, first we must find out how much lou pays for health and disability insurance for a year total, then divide that number by 12, for each month of the year to find out how much he pays monthly. The calculation and answer would be the following: ((Health insurance cost * 30%) + (Disability cost * 10%)) / 12 = (1140+120)/12 = $105 monthly
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Read 2 more answers
6th grade math i mark as brainliest
Natasha_Volkova [10]

Answer:

16

Step-by-step explanation:

8 0
4 years ago
A dealership is having a sale in which customers pay 85% of the retail price for a new vehicle. Keith is buying a vehicle with a
bazaltina [42]
85% of 36000 is 30600
9% of 30600 is 2754
30600 - 2754 = 27846

I'm fairly sure that's right, but I wouldn't say no to a second opinion
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3 years ago
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