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slega [8]
3 years ago
14

Please help. i dont understand what i have to do and how to get it. thank you

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

\left[\begin{array}{ccc}9\\10\\\end{array}\right]

Step-by-step explanation:

Evaluate 3a by multiplying each element by 3

3a = 3 \left[\begin{array}{ccc}2\\4\\\end{array}\right] = \left[\begin{array}{ccc}3(2)\\3(4)\\\end{array}\right] = \left[\begin{array}{ccc}6\\12&\\\end{array}\right], then

3a + b

= \left[\begin{array}{ccc}6\\12\\\end{array}\right] + \left[\begin{array}{ccc}3\\-2\\\end{array}\right] ← sum corresponding elements

= \left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]

= \left[\begin{array}{ccc}9\\10\\\end{array}\right]

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Solve 3v−8v+7v=24. I need help on this question in math
Lyrx [107]

Answer:

v=12

Step-by-step explanation:

3v-8v+7v=24

3v-v=24

2v=24

v=12

3 0
3 years ago
I need help please it would mean alot
earnstyle [38]

Answer:

It would be Step 3

3 0
2 years ago
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10 points! I will thanks, rate, and give best answer!!
vfiekz [6]
Answer: The fourth term is -102

----------------------------------------------

Explanation:

The term after the nth term is generated by this rule  a_{n+1} = -4(a_n) + 2 which means that we first
Step 1) multiply the nth term ( a_n ) by -4
Step 2) Add the result of step 1 to the value 2 to get the next term in the sequence

Let's follow those steps above to generate the first four terms

The first term is a_1 = 2. In short, the first term is 2

The second term is...
a_{n+1} = -4(a_n) + 2
a_{1+1} = -4(a_1) + 2
a_{2} = -4(2) + 2
a_{2} = -8 + 2
a_{2} = -6
So the second term is -6

The third term is...
a_{n+1} = -4(a_n) + 2
a_{2+1} = -4(a_2) + 2
a_{3} = -4(-6) + 2
a_{3} = 24 + 2
a_{3} = 26
The third term is 26

Finally, the fourth term is...
a_{n+1} = -4(a_n) + 2
a_{3+1} = -4(a_3) + 2
a_{4} = -4(26) + 2
a_{4} = -104 + 2
a_{4} = -102
The fourth term is -102.
4 0
3 years ago
Picture shows question
GalinKa [24]
All work is show in the picture below.

5 0
3 years ago
How to change 3 7/8 into an improper fraction
VladimirAG [237]
3 7/8

So we can use this a \frac{b}{c} = \frac{(a \times c) + b}{c}

So we get

3 \frac{7}{8} = \frac{(3 \times 8) + 7}{8}

= \frac{24+7}{8} = \frac{31}{8}
6 0
3 years ago
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