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3 years ago

T + 250 ≤ 600 t ≤ ____?

Mathematics

2 answers:

Viefleur [7K]3 years ago

7 0

T would have to be less than or equal to 350.

saul85 [17]3 years ago

7 0

Answer:

hope this help!!

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Five years ago, John’s age was half of the age he will be in 8 years. How old is he now?

Stella [2.4K]

Answer:

Step-by-step explanation:

x-5=(x+8)/2

x-5=x/2+4

add 5

x=x/2+9

subtract x/2

x/2=9

times 2

x=18

6 0

3 years ago

0=x^2-20 can you solve using square root formula? Then by using quadratic formula?

Nastasia [14]

Sqrt(x^2) = sqrt(20)

x = +2sqrt(5)
x = -2sqrt(5)

x1 = (- 0 + sqrt(0^2 - 4*1*(-20))) / (2*1)
X2 = (-0 - sqrt(0^2 - 4*1*(-20))) / (2*1)

8 0

3 years ago

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

4 years ago

3/4n=675 what is the answer to N

densk [106]

1) 506.25
2) 20
3) x = -1
4) x = 5
Hope this Helps

6 0

3 years ago

Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO

kykrilka [37]

Let c > 0. Then split the integral at t = c to write

$f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt$

By the FTC, the derivative is

$\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}$

8 0

3 years ago