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slava [35]
3 years ago
6

Use C1V1 = C2V2 to calculate the molarity of a potassium bromide solution that is prepared by adding 125mL mL of water to 25mL m

L of aqueous 2.00 M potassium bromide solution. Assume volumes are additive, and report your answer to three significant figures.
Chemistry
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer: 0.4M

Explanation:

This would be much easier if we first analized what was given from the question. This is illustrated below:

C1 = 2M

V1 = 25mL

C2 =?

V2 = 125mL

C1V1 = C2V2

2x25= C2 x 125

Divide both side by 125, we have:

C2 = (2x25) /125

C2 = 0.4M

Therefore, the molarity of potassium bromide formed will be 0.4M

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Answer:

The pressure will be 4.27 atm.

Explanation:

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Where P = pressure, T = temperature, K = Constant

This law indicates that the quotient between pressure and temperature is constant.

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In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 4 atm
  • T1= 20 C= 293 K (being 0 C= 273 K)
  • P2= ?
  • T2= 40 C= 313 K

Replacing:

\frac{4 atm}{293 K} =\frac{P2}{313 K}

Solving:

P2= 313 K* \frac{4 atm}{293 K}

P2= 4.27 atm

<u><em>The pressure will be 4.27 atm.</em></u>

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