*Answer:
Option A: 59.6
Explanation:
Step 1: Data given
Mass of aluminium = 4.00 kg
The applied emf = 5.00 V
watts = volts * amperes
Step 2: Calculate amperes
equivalent mass of aluminum = 27 / 3 = 9
mass of deposit = (equivalent mass x amperes x seconds) / 96500
4000 grams = (9* amperes * seconds) / 96500
amperes * seconds = 42888888.9
1 hour = 3600 seconds
amperes * hours = 42888888.9 / 3600 = 11913.6
amperes = 11913.6 / hours
Step 3: Calculate kilowatts
watts = 5 * 11913.6 / hours
watts = 59568 (per hour)
kilowatts = 59.6 (per hour)
The number of kilowatt-hours of electricity required to produce 4.00kg of aluminum from electrolysis of compounds from bauxite is 59.6 kWh when the applied emf is 5.00V
Answer:
Splitting water molecules produces hydrogen gas, which is used to power machines through hydrogen fuel cells. ( B-)
Answer:
IUPAC name is: 4-methyl-cyclohexanol
Explanation:
IUPAC name is: 4-methyl-cyclohexanol
The hydroxyl group takes precedence over alkyl groups and halogen substituents, as well as double bonds, in the numbering of the parent chain. So in the parent chain i.e. cyclohexane the primary carbon will be the one connected to -OH group. Hence the carbon attatched to methyl group is 4. So the nomenclature is 4-methyl-cyclohexan-1-ol (or) wriiten as 4-methyl-cyclohexanol
Acidic solutions turn litmus paper red.
Answer:
-7612.5 kJ.
Explanation:
Equation of the reaction:
C18H36O2 + 26O2(g) --> 18H2O(g) + 18CO2(g)
ΔHrxn = ΔHp - ΔHr
ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]
= [18 * (-394) + 18 * (-242)] - [1 * (-948) + 26 * (0)]
= [(-7092) + (-4356)] - (-948)]
= -10500 kJ/mol
Molar mass:
C18H36O2;
= (18*12) + (36*1) + (2*16)
= 284 g/mol
O2:
= (2 * 16)
= 32 g/mol
Number of moles = mass/molar mass
C18H36O2:
= 206/284
= 0.725 mol.
O2:
= 943.2/32
= 29.475 mol
Finding the limiting reagent,
By stoichiometry, 1 mole of steric acid combusted in 26 moles of oxygen.
Therefore,
= 29.475 mol of O2 * 1 mol of steric acid/26 mol of O2
= 1.134 mol of steric acid(only 0.725 mol is present)
Steric acid is the limiting reagent.
q = n * ΔHrxn
= 0.725 * -10500
= -7612.5 kJ.
